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Binary Tree Level Order Traversal
mediumPerform a breadth-first traversal of a binary tree and return the node values grouped by depth level. Each level's values should be listed from left to right.
Examples
Example 1:
Input:
root = [10,5,15,3,7,null,20]Output:
[[10],[5,15],[3,7,20]] Example 2:
Input:
root = [42]Output:
[[42]]Hints
import java.util.*;
class Solution {
public List<List<Integer>> levelOrder(TreeNode root) {
List<List<Integer>> result = new ArrayList<>();
if (root == null) return result;
Queue<TreeNode> queue = new LinkedList<>();
queue.offer(root);
while (!queue.isEmpty()) {
int size = queue.size();
List<Integer> level = new ArrayList<>();
for (int i = 0; i < size; i++) {
TreeNode node = queue.poll();
level.add(node.val);
if (node.left != null) queue.offer(node.left);
if (node.right != null) queue.offer(node.right);
}
result.add(level);
}
return result;
}
}Time complexity
O(n)Space complexity
O(n)